x+[latex] frac{x-15}{2} [/latex]=(x-15)·2 Prosze o rozwiazanie Dam naj

[latex] frac{x-15}{2} [/latex] = 2x-30  /razy 2 x-15 = 4x-60  /-x -15 = 3x-60  /+60 45 = 3x  /:3 x = 15

[latex]x+frac{x-15}{2} = (x-15)cdot2 \ \ x+frac{x-15}{2} = 2x-30 / cdot2 \ \ 2x+x-15 = 4x-60 \ \ 2x+x- 4x=-60 +15 \ \ - x=-45 /:(-1)\ \ x=45[/latex]