ROZWIAZ ROWNANIA :  a) [latex]2x - 1 frac{1}{3} = -3 frac{2}{5} [/latex] b) -x + 3 + 5,7 c) 3(x-3) = 6 (2x+1) d) 4(x-3) - (x-1) = 12 - 2x PROSZEEEE :)

a) 2x - 1 i 1/3 = - 3 i 2/5 2x= - 3 i 2/5 + 1 i 1/3 2x = - 3 i 6/15 + 1 i 5/15 2x= - 2 i 1/15 spr. 2x - 1 i 1/3 = - 3 i 2/5 L= 2x - 1 i 1/3 = - 2 i 1/15 - 1 i 1/3= - 2 i 1/15 - 1 i 5/15= - 3 i 6/15= - 3 i 2/5 P= - 3 i 2/5 L=P b)  -x + 3 + 5,7 Nie wiem gdzie powinien być znak "=". Rozwiążę to równanie gdy je poprawisz c) 3(x-3) = 6 (2x+1) 3x - 9 = 12x + 6 3x - 12x= 6 + 9 - 9x = 15 x = 15 : (-9) x= - 15/9 x= - 1 i 6/9 x= - 1 i 2/3 spr. 3(x-3) = 6 (2x+1) L= 3(x-3) = 3(-1 i 2/3 -3) = 3* (-4 i 2/3) = 3 * (-14/3) = 1 * (-14/1) = - 14/1= -14 P= 6(2x +1) = 6(2*(-1 i 2/3) +1) = 6*(2*(-5/3) +1)= 6*(-10/3 +1) = 6*(-10/3 + 3/3) = 6*(-7/3)= 2*(-7/1) = - 14/1 = - 14 L=P d) 4(x-3) - (x-1) = 12 - 2x 4x - 12 - x + 1 = 12 - 2x 3x - 11= 12 - 2x 3x + 2x = 12 + 11 5x= 23 x= 23 : 5 x= 23/5 x= 4 i 3/5 spr. 4(x-3) - (x-1) = 12 - 2x L= 4(x -3) - (x -1) = 4(4 i 3/5 -3) - (4 i 3/5 -1)= 4*1 i 3/5 - 3 i 3/5= 4*8/5 - 3 i 3/5= 32/5 - 3 i 3/5= 6 i 2/5 - 3 i 3/5= 5 i 7/5 - 3 i 3/5= 2 i 4/5 P= 12 - 2x= 12 -2*4 i 3/5= 12 - 2*23/5= 12 - 46/5= 12 - 9 i 1/5= 11 i 5/5 - 9 i 1/5= 2 i 4/5 L=P