oblicz granicę ciągu a) 2n²-6n+1/4n²-5n-3= b) (3n+1)²/(4n-3)²= BŁAGAM SZYBKO

[latex]limlimits_{n o infty}dfrac{2n^2-6n+1}{4n^2-5n-3}=[/latex] [latex]limlimits_{n o infty}dfrac{2-frac{6}{n}+frac{1}{n^2}}{4-frac{5}{n}-frac{3}{n^2}}=[/latex] [latex]dfrac{2-0+0}{4-0-0}=dfrac{1}{2}[/latex] --- [latex]limlimits_{n o infty}dfrac{(3n+1)^2}{(4n-3)^2}=[/latex] [latex]limlimits_{n o infty}dfrac{9n^2+6n+1}{16n^2-24n+9}=[/latex] [latex]limlimits_{n o infty}dfrac{9+frac{6}{n}+frac{1}{n^2}}{16-frac{24}{n}+frac{9}{n^2}}=[/latex] [latex]dfrac{9+0+0}{16-0+0}=dfrac{9}{16}[/latex]