Zad 1. 2^10+2^10= Zad 2. 2*3^20-5*3^19 kreska ułamkowa 9^9= Zad 3. (1/60^-2+√144= Zad 4. √1,5^2 - 0,9^2= BARDZO POLNE DAM NAJ I 50 PKT.....

zad.1 [latex]2^{10}+2^{10}=2cdot 2^{10}=2^{1+10}=2^{11}[/latex] zad.2 [latex]frac{2cdot 3^{20}-5cdot 3^{19}}{9^9}=frac{3^{19}(2cdot 3-5)}{(3^2)^9} = frac{3^{19}cdot 1}{3^{18}}=3^{19-18}=3[/latex] zad.3 [latex](frac{1}{60})^{-2} sqrt{144}=60^2-12 = 3600-12 = 3588[/latex] zad.4 [latex]sqrt{1,5^2}-0,9^2= 1,5-0,81 = 0,69[/latex]

[latex] frac{2*3^2^0-5*3^1^9}{9^9} = frac{2*(3^2)^1^0}{9^9} - frac{5*(3^2)^9}{9^9} = frac{2*9^1^0}{9^9} - frac{5*9^9}{9^9} =18-5=13[/latex] [latex] frac{1}{60} ^-^2+ sqrt{144} =60^2+12=3600+12[/latex] [latex] sqrt{1,5^2} -0,9^2=1,5-0,81=0,69[/latex]