Dam Naj Pilne Oblicz granice: lim x->2 (x^2-3x+2)/(3x^2-6x) .Proszę o obliczenia

[latex] lim_{x o 2} dfrac{x^{2} - 3x + 2}{3x^{2} - 6x} = lim_{x o 2} dfrac{x^{2} - 2x - x +2}{3x(x-2)} = \ \ = lim_{x o 2} dfrac{x(x-2) -(x-2) }{3x(x-2)} = lim_{x o 2} dfrac{(x-1)(x-2)}{3x(x-2)} = \ \ = lim_{x o 2} dfrac{x-1}{3x} = dfrac{2-1}{3 cdot 2} = oxed{ dfrac{1}{6} }[/latex]