rozwiaz rownanie 1. -x^3-8x^2+x-8=0 2. x^7-5x^5+4x^3=0

[latex]1.\x^3-8x^2+x-8=0\x^2(x-8)+x-8=0\(x-8)(x^2+1)=0\x-8=0 lub x^2+1=0\x=8\x^2=-1 sprzeczne\Odp: x=8\ \2.\x^7-5x^5+4x^3=0\x^3(x^4-5x^2+4)=0\x=0 lub x^4-5 x^2+4=0\x^2=t\tgeq0\t^2-5t+4=0\Delta=(-5)^2-4*1*4=25-16=9\sqrtDelta=3\t_1= frac{5-3}{2}=1\t_2= frac{5+3}{2}=4\x=1\x=-1\lub\x=2\x=-2[/latex] Odp: x=0, x=-1, x=1, x=-2, x=2