λ = 97 x 10⁻⁹m h = 6,63 x 10⁻³⁴Js c = 3 x 10⁸m/s E = hc/λ E = 6,63 x 10⁻³⁴Js x 3 x 10⁸m/s / 97 x 10⁻⁹m = 0,2 x 10⁻¹⁷J ≈ 12,5eV E₁ = -13,6eV En = -13,6eV + 12,5eV = -1,1eV En = E₁/n² => n = √E₁/En n = √-13,6eV/-1,1eV ≈ 4 ---------------------------------------------------------------------------------------------------- Litterarum radices amarae sunt, fructus iucundiores Pozdrawiam :)
[latex]Dane:\ E_1=-13,6eV\ lambda=97nm=0,97*10^{-7}m\ c=3*10^8frac{m}{s}\ h=4,14*10^{-15}eVs\ Oblicz:\ n=?\ Rozwiazanie:\ Ef=frac{hc}{lambda}\\ Ef=frac{4,14*10^{-15}*3*10^8}{0,97*10^{-7}}\\ Ef=12,8eV\\ E_n=E_1+Ef\ E_n=-13,6+12,8\ E_n=-0,8\\ E_n=frac{E_1}{n^2}Rightarrow n=sqrt{frac{E_1}{E_n}}\\ n=sqrt{frac{-13,6}{-0,8}}\\ n=sqrt{17}\\ n=4,17approx 4[/latex]
