(x+1)(x-2)+(x+2)(x-1)= (5k+n)(k-2n)-k(4k+n)= (4y+3)(y-2)-2y(4-2y)=
(x+1)(x-2)+(x+2)(x-1)=
(5k+n)(k-2n)-k(4k+n)=
(4y+3)(y-2)-2y(4-2y)=
Odpowiedź
x² - 2x + x - 2 + x² - x + 2x - 2 = x⁴ - 4 5k² + 10kn + kn - 2n² - 4k² - kn = k² + 10kn - 2n² 4y² - 8y + 3y - 6 - 8y + 4y² = 8y² - 13y - 6
(x+1)(x-2)+(x+2)(x-1)=2x^2 - 4=2(x+2)(x-2) (5k+n)(k-2n)-k(4k+n)=k^2 - 10kn - 2n^2 (4y+3)(y-2)-2y(4-2y)=8y^2 - 13y - 6
(x+1)(x-2)+(x+2)(x-1)=x²+x-2x-2+x²-x+2x-2=2x²-4 (5k+n)(k-2n)-k(4k+n)=5k²-10kn+kn-2n²-4k²-kn=k²-2n²-10kn (4y+3)(y-2)-2y(4-2y)=4y²-8y+3y-6-8y+4y²= 8y²-13y-6
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