A) (x + 1)^/3 - (2 - x) = 1/3 (x^ - 10)

(x + 1)²/3 - (2 - x) = 1/3 (x² - 10) (x² + 2x + 1) - 3(2-x) = x² - 10 x² + 2x + 1 - 6 + 3x = x² - 10 5x = -5 x = -1

x^+2x+1/3-2+x=1/3x^-10/3 /*3 x^+2x+1-6+3x=x^-10 x^-x^+2x+3x=-10+6-1 5x=-5 /:5 x=-1