Pomóżcie!! to na jutro:/ Oblicz układem równań: 4x+3y=54 ⅓x=4(1+⅛y) z góry dzięki! :)))

4x+3y=54 1/3x=4(1+1/8y) 4x+3y=54 1/3x=4+1/2y /6 4x+3y=54 2x=3y+4 4x+3y=54 + 2x-3y=4 6x = 58 //6 x=9 i 2/3 4* 9i2/3+3y=54 3y=54-38i2/3 3y=15i1/3 //3 y=5i1/9 spr. 4* 9i2/3= 38i2/3 3*5i1/9=15i1/3 38i2/3+15i1/3=54

4x * 3y = 54 1/3x = 4(1 = 1/8y) 4x * 3y = 54 1/3x = 4 + 4/8y /*24 4x * 3y = 54 8x = 96 + 12y /:4 4x * 3y = 54 2x = 24 + 3y 4x * 3y = 54 2x - 3y = 24 ------------------ + 6x = 78 /: 6 x = 13 2x - 3y = 24 x = 13 2*13 - 3y = 24 x = 13 26 - 3y = 24 x = 13 -3y = -2 x = 13 3y = 2 x = 13 y = 1,5 x = 13