Zapisz w jak najprostszej postaci: a) (x + 4) + (2x - 6) = b) -(2y + 3x) + (-4y + 2x + 1) = c) -(x - 2xy) - (4x + xy) + (xy - x) = d) (x^[do kwadratu] + 2x + 1) - (x^[do kwadratu] - 4x + 3) = Proszę rozwiążcie mi to zadanie.

a) (x + 4) + (2x - 6) =x+4+2x-6=3x-2 b) -(2y + 3x) + (-4y + 2x + 1) =-2y-3x-4y+2x+1=-6y-x+1 c) -(x - 2xy) - (4x + xy) + (xy - x) =-x+2xy-4x-xy+xy-x=-6x+2xy d) (x² + 2x + 1) - (x² - 4x + 3) =x²+2x+1-x²+4x-3=6x-2 Pozdro:)

a) (x + 4) + (2x - 6) =x+4+2x-6=3x-2 b) -(2y + 3x) + (-4y + 2x + 1) = -2y -3x -4y +2x +1= -6y -x +1 c) -(x - 2xy) - (4x + xy) + (xy - x) = -x +2xy -4x -xy +xy -x= -6x +2xy d) (x² + 2x + 1) - (x² - 4x + 3) = x²+2x+1-x²+4x-3=6x-2