a) (½)⁶-(½)⁷= b) (3⁻¹+2⁻²)⁻²+4⁻¹:[2/7]⁻²+2/49=

a) 1/64-1/128=1/128 b) (1/3+1/4)^-2+1/4:(49/4)+2/49= 144/49+1/49+2/49=147/49=3

a) (½)⁶-(½)⁷=(½)⁶*(1-½)=(½)⁶*(½)=(½)⁷=1/128 b) (3⁻¹+2⁻²)⁻²+4⁻¹:[2/7]⁻²+2/49= =(1/3+(1/2)²)⁻²+1/4:(7/2)²+2/49=(1/3+1/4)⁻²+(1/4)*(4/49)+2/49= =(4/12+3/12)⁻²+(1/49)+(2/49)= =(7/12)⁻²+3/49=(12/7)²+(3/49)=144/49+3/49=147/49=3

a)1/64-1/128=-1/64 b)9+16+1/4:49/4+2/49=25 3/49