rozwiaz uklady rownan: 10(y+2)+3(x-5)=x-5 25(y+2)+3(x-5)=-10 prosze o pomoc!! :]

10(y+2)+3(x-5)=x-5 25(y+2)+3(x-5)=-10 10y+20+3x-15=x-5 25y+50+3x-15=-10 10y+3x-x=-5-20+15 25y+3x=-10-50+15 10y+2x=-10/ * (-2,5) 25y+3x=-45 -25y-5x=25 25y+3x=-45 -5x+3x=25-45 -2x=-20 / : (-2) x=10 25y + 3*10=-45 25y + 30 = -45 25y=-45-30 25y=-75 / : 25 y= -3 x=10 y=-3

10(y+2)+3(x-5)=x-5 25(y+2)+3(x-5)=-10 10y+20+3x-15-x=-5 25y+50+3x-15=-10 10y+2x=-10 /*(-3) 25y+3x=-45 /*2 -30y-6x=-30 50y+6x=-90 20y=-120 /20 y=-6 10y+2x=-10 10*(-6)+2x=-10 -60+2x=-10 2x=50 x=25

{10(y+2)+3(x-5)=x-5 {25(y+2)+3(x-5)=-10 {10y+2x=-10 /:2 {25y+3x=-45 {5y+x=-5 /*(-3) {25y+3x=-45 {-15y-3x=15 +{25y+3x=-45 10y=-30 / :10 y=-3 {5*-3+x=-5 {y=-3 {-15+x=-5 {y=-3 {x=10 {y=-3 Spr: {10(-3+2)+3(10-5)=10-5 {25(-3+2)+3(10-5)=-10 {10*(-1)+3*5=5 {25*(-1)+3*5=-10 {-10+15=5 {-25+15=-10 {5=5 {-10=-10 L=P