Zapisz w jak najprostszej postaci (5k+n)(k-2n)-k(4k+n) -(3c-2)(c-1)-c(c-2)

(5k+n)(k-2n)-k(4k+n)= =5k² -10kn +kn-2n²-4k²-kn= =k²-10kn-2n² -(3c-2)(c-1)-c(c-2) = = -(3c²-3c-2c+2)-c²+2c= =-3c²+3c+2c-2-c²+2c= = -4c²+7c-2 :)

a)(5k+n)(k-2n)-k(4k+n)= =5k² -10kn +kn-2n²-4k²-kn= =k²-10kn-2n² b)-(3c-2)(c-1)-c(c-2) = = -(3c²-3c-2c+2)-c²+2c= =-3c²+3c+2c-2-c²+2c= = -4c²+7c-2