x²+4x-5-0

x²+4x-5-0 delta = b^2 - 4ac = 4^2 + 4*1*5=16+20=36 pierwiastek z dety = 6 bo 6*6=36 obliczny teraz x1 i x2 X1 = ( -b -pierwiastek z dety)/2a = (-4-6)/2=-10/2=-5 x2 = ( -b +pierwiastek z dety)/2a=(-4+6)/2=2/2=1 x²+4x-5=(x+5)*(x-1)