oblicz masę cząsteczkową propanolu, dekanonlu 3 gim

C3H7OH= 36+ 7+ 16+1=60u C10H21OH= 120+ 21+16+1=158u

propanol - C₃H₇OH mC₃H₇OH= mC₃+mH₇+mOH mC3H7OH=3*12u+7*1u+16u+1u=36u+7u+17u=60u dekanol - C10H21OH mC10H21OH= 10 * 12u+21*1u+16u=120u+21u+17u=158u