rozwiąż równania a )3x do kwadratu +6= 3x(x-2) b) (x + 2 ) (3 +x )=x(x+1 ) +2

3x do kwadratu +6= 3x(x-2) 3x do kwadratu +6=3x do kwadratu -6x / -3x do kwadratu 6=-6x /:-6 -1=x (x + 2 ) (3 +x )=x(x+1 ) +2 3x+x do kwadratu +6+2x=x do kwadratu +x +2 /-x do kwadratu 5x + 6= x+2 /-x 4x +6 =2 /-6 4x=-4 / :4 x=-1

a )3x do kwadratu +6= 3x(x-2) 3x² + 6 = 3x² -6x 3x² -3x² +6x = -6 6x = -6 /:(6) x = -1 b) (x + 2 ) (3 +x )=x(x+1 ) +2 3x + x² + 6 +2x = x² +x +2 5x + x² +6 = x² +x +2 5x + x² - x² -x = 2 - 6 4 x = -4 /:4 x = -1

(x+2)(3+x)=x(x+1)+2 3x+ x kwadrat+6+2x= x kwadrat+x+2 3x+2x-x=2-6 4x=-4 |:4 x=-1