rozwiaz uklad rownan 4(2x+3)-2(4y-1)=30 5x+1/3-y-3/4=3 BŁAGAM

4(2x+3) - 2(4y-1)=30 8x+12-8y+2=30 8x-8y=30-14 8x-8y=16 5x+1/3 -y- 3/4=3 /* 12(wspólny mianownik dla 3 i 4) 60x +4-12y -9=36 60x - 12y=36-4+9 60x-12y=38

4(2x+3)-2(4y-1)=30 5x+1/3-y-3/4=3 8x+12-8y+2 =30 5x+1=9-3y-9/4 8x-8y=16 |x3 5x+3y=5 i 3/4 |x8 24x-24y=48 40x+24y=46 64x=94 x=94/64 16- 8 *(94/64) = -8y -8y= 11 i 3/4 y=-94 x= 94/64

a) 8x+12-8y+2=30 8x-8y+14-30=0 8x-8y-16=0 Δ=8²-4*8*(-16) Δ=64+512 Δ=(pierwiastek) 576= 34 x₁=8-24/ 16 x₁=(-1) x₂=8+24/ 16 x₂=2 b) 5x+1/3 - y - 3/4 = 3 /*12 60x+4-12y-9-3=0 60x-12y-16=0 /4 15x-3y-4=0 Δ=9+240=15,8 x₁=9-(pierw z 15,8 /30 x₁= 3- pier 15,8 / 10 x₂=3+pierw z 15,8 / 10