a) 3x=12 x-y=1 x=4 4-y=1 y=3 b) 4y-x=6 17y=0 y=0 x=4y-6 x=-6 c) u=4v 5u-v=10 20v-v=10 19v=10 v=10/19 u=40/19
a) 3x = 12 x - y = 1 3x = 12 :3 x = 4 x - y = 1 4 - y = 1 -y = 1-4 y = 3 b) 4y - x = 6 17y = 0 4y = x +6 :4 y = ¼x + 1,5 17(¼x + 1,5) = 0 4,25x + 25,5 = 0 4,25x = -25,5 |: (4,25) x = -6 4y - x = 6 4y = 6 - 6 4y = 0 |:4 y = 0 c) u = 4v 5u - v = 10 5*4v - v = 10 20v - v = 10 19v = 10 |:19 obie opcje sa dobre v = 0,53 lub v = 10/19 u = 4*0,53 lub u = 4*10/19 u = 2,12 lub u = 40/19 = 2 i 2/19
a) {3x=12/3 {x-y=1 {x=4 {4-y=1 {x=4 {-y=1-4 {x=4 {y=3 b) {4y-x=6 {17y=0/17 {4y-x=6 {y=0 {4*0-x=6 {y=0 {-x=6/*(-1) {y=0 {x=-6 {y=0 c) {u=4v {5u-v=10 5*4v-v=10 20v-v=10 19v=10 v=10/19 u=4*10/19 u=40/19 u=2²/₁₉