a) (x+1)(x+2)(x+3)= = (x²+2x+x+2)(x+3)= =x³+3x³+2x²+6x+3x+x²+2x+6= 4x³+3x²+12x+6 b) (x-2)(x+5)(2x-1)= = (x²+5x-2x-10(2x-1)= = 2x³-x²+10x²-5x-4x²+2x-20x+10= = 2x³+5x²-23x+10 c)(x-4)(x+1)²= (x-4)(x²+1+2x)= =x³+x+2x²-4x²-4-8x= =x³-2x²7x-4 d)(2x-3)²(x+2)= =(4x²+9-12x)(x+2)= = 4x³+9x-12x²+8x²+18-24x= = 4x³-4x²-15x+18 Mam nadzieje ze się gdzieś nie machnęłam :):):)
zad. Zapisz w postaci sumy algebraicznej: a) (x+1)(x+2)(x+3)= (x²+2x+x+2)(x+3)=(x²+3x+2)(x+3)= =x³+3x²+3x²+9x+2x+6=x³+6x²+11x+6 c)(x-4)(x+1)²=(x-4)(x²+2x+1)=x³+2x²+x-4x²-8x-4=x³-2x²-7x-4 b) (x-2)(x+5)(2x-1)=(x²+5x-2x-10)(2x-1)=(x²+3x-10)(2x-1)= =2x³-x²+6x²-3x-20x+10=2x³+5x²-23x+10 d) (2x-3)²(x+2)=(4x²-12x+9)(x+2)=4x³+8x²-12x²-24x+9x+18= =4x³-4x²-15x+18
