Ile gramów NaOH potrzeba do zobojętnienia 6 gramów CH3COOH? Szyyybko... :D Proszę.xD

CH3COOH + NaOH = CH3COONa + H2O 6 g ---------- x g 60 g --------- 40 g x = 4 g

CH3COOH + NaOH = CH3COONa + H2O mCH3COOH = 60g mNaOH = 40g W jednym molu mamy 60g CH3COOH i 40g NaOH, tak więc układamy proporcję: 60 g CH3COOH ----- 6g 40g NaOH ------- xg 60x = 40g * 6g 60x = 240g / : 60 x = 4g Potrzeba 4g NaOH

CH3COOH + NaOH = CH3COONa + H2O 60g ------ 40g 6g ------ xg x = 4 g Odp. Potrzeba 4g NaOH.