rozwiaz równanie metoda podstawiania 4(x+2)=1-5y {3(y+2)=3-2x 3(x-1)=4y+1 5(y-1)=x+1

4(x+2)=1-5y {3(y+2)=3-2x 4x+8=1-5y 3y+6=3-2x 4x = 1-5y -8 /4 3y+6=3-2x x=1/4 - 5/4 - 2 3y+6=3-2x 3y+6=3-2(1/4-5/4-2) 3y+6= 3 - 1/2 + 5/2 + 4 3y = 11/2 / : 3 y = 11/6 3(x-1)=4y+1 5(y-1)=x+1 3x - 3 = 4y+1 5y-5=x+1 3x - 3 = 4y+1 5y-5-1=x 3(5y-5-1)-3=4y+1 15y-15-3-3=4y+1 15y-4y=1+15+3+3 11y=24 / :11 y = 24/11 nie wiem czy dobrze , bo już późno :D

4(x+2)=1-5y 3(y+2)=3-2x 4x + 8 = 1 - 5y 3y + 6 = 3 - 2x 4x = -7 + 5y | :4 3y + 6 = 3 - 2x x = -7/4 + 5y/4 3y + 6 = 3 - (-7/4 + 5y/4) x = -7/4 + 5y/4 3y + 6 = 3 + 1 3/4 - 5y/4 x = -7/4 + 5y/4 3y + 5y/4 = 4 3/4 - 6 x = -7/4 + 5y/4 3y + 5y/4 = -1 3/4 | *4 x = -7/4 + 5y/4 12y + 5y = -7 x = -7/4 + 5y/4 17y = -7 Dalej nie umiem :P

3(x-10)=4y+1 5(y-1)=x+1 3x-3=4y+1 5y-5=x=1 3x-4y=4 5y-x=6 3x-4y=4 -x=6-5y/ :(-1) 3x-4y=4 x=-6+5y 3(-6+5y)-4y=4 x=-6=5y -18+15y-4y=4 x=-6=5y 11y=22 /(-1) x=-6+5y y=2 x=-6+5y x=-6+10 y=2 x=4 y=2