Oblicz: a)Log20+log5= Zapisz w postaci potęgi: 9^12 : 27^5=

[latex]log_{a}b+log_{a}c = log_{a}b*c[/latex]log 20 + log 5 = log 100 = 2bo 10² = 100[latex]frac{9^{12}}{27^{5}} = frac{(3^{2})^{12}}{(3^{3})^{5}} = frac{3^{24}}{3^{15}} = 3^{9}[/latex]

[latex]log20+log 5=log(20 cdot 5)=log 100 = 2[/latex] [latex]9^{12}:27^5=(3^2)^{12}:(3^3)^5=3^{24}:3^{15}=3^{24-15}=3^9[/latex]