Zapisz w postaci sumy albebraicznej: a) (2a+b)×c-(2ac-bc+1) b)5(x-z)+2(z-x) c)2x²(x-5)-3x(x²-3x+5) d)6(a²+b+⅓)-6(a²-½)-3(b+⅓)

a) (2a+b)×c-(2ac-bc+1)=2ac+bc-2ac+bc-1=2bc-1 b)5(x-z)+2(z-x)=5x-5z+2z-2x=3x-3z c)2x²(x-5)-3x(x²-3x+5)=2x³-10x²-3x³+9x²-15x=-x³+x²-15x d)6(a²+b+⅓)-6(a²-½)-3(b+⅓)=6a²+6b+2-6a²+3=6b+5

a) 2ac+bc-2ac+bc+1=2bc+1 b)5x-5z+2z-2x=3x-3z c)2x³-10x²-3x³+9x²-15x=-x³-x²-15x d) 6a²+6b+2-6a²-3-3b+1= 3b

Zapisz w postaci sumy albebraicznej: a) (2a+b)×c-(2ac-bc+1)=2ac+bc-2ac+bc-1= 2bc-1 b)5(x-z)+2(z-x)=5x-5z+2z-2x= 3x-3z= 3(x-z) c)2x²(x-5)-3x(x²-3x+5)=2x³-10x²-3x³+9x²-15x= -x³-x²-15x= -x(x²+x+15) d)6(a²+b+⅓)-6(a²-½)-3(b+⅓) =6a²+6b+2-6a²+3-3b-1= 3b+4