x³-7x²2x-14=0

x³-7x²+2x-14=0 x(x²+2)-7(x²+2)=0 (x-7)(x²+2)=0 x=7

x^2(x-7) + bo nie napisales 2(x-7)=0 (x-7)(x^2+2)=0 jak tam byl plus to tak x={7}

x³-7x²*2x-14=0 x³-14x³-14=0 -13x³-14=0 -13x³=14 x³=14:(-13) x=∛[-(14:13)]