1.(2x-1)² – (y-2)² = 2(x+3)² - 0,5(1-y) - tu jest podzielić prze dwa;) 2 8x + 2y+6=0 2.(x-y)(x+y)= (x-2)²-(y+3)² 3x+4y=3,2

1.(2x-1)² – (y-2)² = 2(x+3)² - 0,5(1-y) * ½ 4x²+1-y²+4=2(x²+9)-0,5+0,5y*½ 4x²+1-y²-4=2x²+18-0,5+0,5y*½ /*2 8x²+2-2y²-8=4x²+36-1+1*1 8x²-6-2y²=4x²+36 2. 8x + 2y+6=0 /-6 8x+2y=-6 /:2 4x+y= -3 /-4x y=-3 - 4x 3. (x-y)(x+y)= (x-2)²-(y+3)² x²+xy-xy-y²= x²+4 - y² + 9 x²-y²=x²-y²+13 4. 3x+4y=3,2 /-3x 4y=3,2-3x /:4 y=0,8 - 0,75x