1.Podaj rozwiązanianastępujących układów równań: a) 4(x-2)-(y-2)=1 10x-2y=18 b)2x-4(y+1)=10 2(x+3)-(1-y)=9

a) 4(x-2)-(y-2)=1 4x-8-y+2=1 (4x-y=7 (10x-2y=18 (-8x+2y=-14 (10x-2y=18 2x=4 x=2 y=1 b) 2x-4(y+1)=10 2(x+3)-(1-y)=9 (2x-4y=14 (2x+y=4 (2x-4y=14 (-2x-y=-4 -5y=10 y= -2 x= 3

a) 4(x-2)-(y-2)=1 10x-2y=18 4x - 8 - y + 2 = 1 10x - 2y = 18 4x - y = 1 + 8 - 2 |*(-2) 10x -2y = 18 -8x +2y = -14 10x - 2y = 18 2x = 4 |:2 x = 2 -2y = 18 - 10x -2y = 18 - 10*2 -2y = 18 - 20 -2y - -2 |:(-2) y = 1 b)2x-4(y+1)=10 2(x+3)-(1-y)=9 2x - 4y - 4 = 10 2x + 6 - 1 + y = 9 2x - 4y = 10+4 |*(-1) 2x + y = 9 - 6 + 1 -2x + 4y = -14 2x + y = 4 5y = -10 |:5 y = -5 2x = 4-y 2x = 4 - (-5) 2x = 4+5 2x = 9 |:2 x = 4,5

a) 4(x-2)-(y-2)=1 10x-2y=18 4x-8-y+2=1 10x-2y=18 4x-y=1+8 10x-2y=18 4x-y=9 /*(-2) 10x-2y=18 -8x+2y=-18 10x-2y=18 2x=0 x=0 10*0-2y=18 0-2y=18 -2y=18 y=-9 b) 2x-4(y+1)=10 2(x+3)-(1-y)=9 2x-4y-4=10 2x+6-1+y=9 2x-4y=10+4 2x+y=9-5 2x-4y=14 2x+y=4 /*(-1) 2x-4y=14 -2x-y=-4 -5y=10 y=-2 2x+(-2)=4 2x-2=4 2x=6 x=3