Oblicz masę 20% roztworu NaOH , potrzebnego do zobojętnienia 126g 10% roztworu HNOз proszę :))

Cp=10% mr=126g ms=Cp*mr/100% ms=10*126/100 ms=12,6g HNO3   mHNO3=63u mNaOH=40u NaOH + HNO3 ---> NaNO3 + H2O 40g NaOH ----- 63g HNO3 xg NaOH ------ 12,6g HNO3 x = 8g NaOH   ms=8g Cp=20% mr=ms*100%/Cp mr=8*100/20 mr = 40g roztworu NaOH