Zapisz w jak najprostszej postaci : (x+3y)^-9y^ = (b+3)^-(b-3)^ = 2(3+b)^-12b = (3x-2)^+2(x+3)^= Znaczek ^ oznacza do kwadratu(do potęgi 2)

(x+3y)^-9y^ =x^+6xy+9y^-9y^ = x^+6xy (b+3)^-(b-3)^ =b^+6b+9 -(b^-6b+9) = b^+6b+9-b^+6b-9=12b 2(3+b)^-12b =2(9+6b+b^)-12b=18+12b+2b^-12b=18+2b^ (3x-2)^+2(x+3)^=9x^-12x+4+2(x^+6x+9)=9x^-12x+4+2x^+12x+18= =22+11x^2

a) (x+3y)^-9y^= x^+6xy+9y^-9y^= x^+ 6xy b) (b+3)^-(b-3)^ =b^+6b+9-(b^-6b+9) = b^+6b+9-b^+6b-9 = 12b c) 2(3+b)^-12b = 2(9+6b+b^)-12b = 18+12b+2b^-12b = 2b^+18 d) (3x-2)^+2(x+3)^= (9x^-12x+4)+2(x^+6x+9) = 9x^-12x+4+2x^+12x+18 = 11x^+22