(3/2)⁻²+(⅓)⁻³ *1/9+(⅗)⁻²=
(3/2)⁻²+(⅓)⁻³ *1/9+(⅗)⁻²=
Odpowiedź
(3/2)⁻²+(⅓)⁻³ *1/9+(⅗)⁻²= (2/3)²+3³*1/9+(5/3)²= 4/9+3+25/9= 29/9+9=3 (cale i) 2/9+3=6 (i) 2/9 ;)
Dodaj swoją odpowiedź
(3/2)⁻²+(⅓)⁻³ *1/9+(⅗)⁻²= (2/3)²+3³*1/9+(5/3)²= 4/9+3+25/9= 29/9+9=3 (cale i) 2/9+3=6 (i) 2/9 ;)