(3b-2)+4(b-1) b=-3 (4x-3)+4(6-1) x= minus jedna piąta

(-9-2)+4(-3-1)=-11-16=-27 (-4/5-3)+20=-19/5+20=-3,8+20=16,2

((3 * (-3)) - 2) + 4 (-3 -1) = (-9 - 2) + 4 * -4 = -11 + 4 * -4 = -11 + (-16) = -11 - 16 = -27 (4 * (- 1/5) - 3) + 4(6-1) = ( - 4/5 - 3) + 4 * 5 = - 3 cale i cztery piate + 20 = 16 i jedna piata = 16,2

(-6-2)+4(-3-1)=-8-12+4=-16