rozwiaz uklad rownan (x+1)*+(y-3)*=16 x-y=0 * to znaczy do kwadratu

(x+1)^2+(y-3)^2=16 ^2 do potęgi drugiej x-y=0 x^2+2x+1+y^2-6y+9-16=0 x=y x^2+2x+1+x^2-6x-7=0 x=y 2x^2-4x-6=0 x=y delta=b^2-4ac=(-4)^2-4*2*(-6)=64 pierw z delty=8 x1= (-b-pierw z delty)/2a=(4-8)/4= -1=y1 x2= (-b+pierw z delty)/2a=(4+8)/4=3=y2

rozwiaz uklad rownan { (x+1)²+(y-3)²=16 x-y=0→→x=y (x+1)²+(x-3)²=16 x²+2x+1+x²-6x+9=16 2x²-4x-6=0 /:2 x²-2x-3=0 Δ=4+12=16 √Δ=4 x₁=-1, x₂=3 y₁=-1, y₂=3