5x(x-2)-x(x-2)<-4= 2-(x-3)≥0,5x-1= x(2-x)+(x+2)(x-2)>2= (x-3)(x+3)-(x-2)²≤19=

5x(x-2)-x(x-2)<-4= 2-(x-3)≥0,5x-1= x(2-x)+(x+2)(x-2)>2= (x-3)(x+3)-(x-2)²≤19=
Odpowiedź

5x(x-2)-x(x-2)<-4= 5x² -10x - x² + 2x < -4 4x² - 8x < -4 4x² - 8x + 4 < 0 delta rowna sie b²- 4ac 8² - 4 * 4 * 4 64 - 64 0 x1 rowna sie -b - delta / 2a 8-0 / 2* 4 8 / 8 1 x1 rowna sie 1 x2 rowna sie -b + delta / 2a 8+0 / 2*4 8/ 8 1 x2 rowna sie 1 2-(x-3)≥0,5x-1 2 - x - 3 ≥ 0.5x - 1 -x - 0,5x ≥ -1 -2 +3 - 1,5x ≥ 0 x(2-x)+(x+2)(x-2)>2 2x - x ² + x² + 2x + 2x - 4 >2 6x - 4 >2 6x > 2 +2 6x > 4 /6 x > 4/6 (x-3)(x+3)-(x-2)²≤19 x² +3x -3x -9 - (x-2)(x-2) ≤19 x² - 9 - (x² - 2x - 2x + 4) ≤19 x² - 9 - x ² + 2x + 2x - 4 ≤19 - 13 + 4x ≤19 4x ≤19 + 13 4x ≤ 32 x ≤ 32 / 4 x ≤ 8

=5x-2x-(2x)<-4=5x-2x+2x=5x =2-(-3x)>1,05x=2+3x>1,05=3x-1,05x>2=1,95>2 =x-2x+2x-2x>2=x>2 =(x-3)(x+3)-(x-4)<19=-3x+3x-(4x)<19=-4x<19

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