Oblicz masy cząsteczkowe podanych związków chemicznych. mCuO= mFe2O3= mNaCO3= mH2SO4= mCa(OH)2= mFe2(SO3)3= PILNIEEEEEEEEEEEEEEEEEEEEEEEEEEE PROSZEEEEEEEEEEEE OOOOOOOOO POMOCCCCCCCCCCCCCCCCCCC!!!!!!!!!!!!!!!!!!!!!!!!!!!!

mCuO= 64u+16u=80u mFe2O3=2*56u+3*16u=112+48=160u mNaCO3=23u+12u+3*12u=71u mH2SO4=2*1u+32u+4*16u=98u mCa(OH)2=40u+(16+1)2=40u+17u*2=40u+34u=74u mFe2(SO3)3=2*56u+(32u+3*16u)3=112u+(32u+48u)3=112u+80u*3=240u+112u= =352u

mFe2O3=2*56u+3*16u=112u+48u=160u mCuO= 64u+16u=80u mNaCO3=23u+12u+3*16u=23u+12u+48u=83u mH2SO4=2*1u+32u+4*16=2u+32u+64u=98u mCa(OH)2=40u+2*16u+2*1u=40u+32u+2u=74u mFe2(SO3)3=2*56u+3*32u+9*16u=112u+96u+144u=352u