Zad;14 a) 2(x+3) =10 2x+6 = 10 2x = 4/ :2 x = 2 b) 3(x-1)+2=8 3x-3 +2 = 8 3x = 9 / :3 x = 3 c) 2(13-x) - 9 = 1 26 - 2x -9 = 1 -2x = -16 / :(-2) x = 8 d) 3(1-x)+2= -7 3 - 3x +2 = -7 -3x = -12 / :(-3) x =4 e) 3(x+3)= 2(x+4) +x+1 3x+9 = 2x +8 +x +1 0 = 0 f) 4(3x+2) + 5(2x+2) = -(2x+13) 12x +8 +10x +10 = -2x -13 20x = -31 / : 20 x = 1,55 g) 4(x-2)-2(x-4) = 5(x+)- 3x 4x -8 -2x +8 = 5x - 3x 0 = 0 h)2(x-4)=2(x-1)+6(x+1) 2x -8 = 2x -2 +6x +6 -6x = 12 / : (-6) x = -2 :)
2(x+3) =10 2x + 6 = 10 2x = 10 - 6 2x = 4 / :2 x = 2 3(x-1)+2=8 3x - 3 + 2 = 8 3x = 8 + 3 - 2 3x = 9 /:3 x = 3 2(13-x) - 9 = 1 26 - 2x - 9 =1 -2x = 1 - 26 + 9 -2x = -16 /:(-2) x = 8 3(1-x)+2= -7 3 - 3x + 2 = -7 -3x = -7 -3 - 2 -3x = -12 /:(-3) x = 4 3(x+3)= 2(x+4) +x+1 3x + 9 = 2x + 8 + x +1 3x - 2x - x = 1 - 9 + 8 0 = 0 układ nieoznaczony, rozwiązaniem może być każda liczba rzeczywista 4(3x+2) + 5(2x+2) = -(2x+13) 12x + 8 + 10x + 10 = -2x -13 12x + 10x +2x = -13 - 8 - 10 24x = -31 / :24 x = -31/21 x= -1 10/21 4(x-2)-2(x-4) = 5(x+)- 3x 4x - 8 - 2x + 8 = 5x - 3x 4x - 2x - 3x - 5x =8-8 -6x = 0 /: (-6) x = 0 2(x-4)=2(x-1)+6(x+1) 2x - 8 = 2x - 2 + 6x + 6 2x - 2x - 6x = 8 + 6 -2 -6x = 12 / (-6) x = -2
a) 2(x+3) =10 2x+6=10 2x=10-6 2x=4/:2 x=2 b) 3(x-1)+2=8 3x-3+2=8 3x=8+3-2 3x=9/:3 x=3 c) 2(13-x) - 9 = 1 26-2x-9=1 -2x=1-26+9 -2x=-16/:(-2) x=8 d) 3(1-x)+2= -7 3-3x+2=7 -3x=-7-3-2 -3x=-12/:(-3) x=4 e) 3(x+3)= 2(x+4) +x+1 3x+9=2x+8+x+1 3x-3x=9-9 0=0 f) 4(3x+2) + 5(2x+2) = -(2x+13) 12x+8+10x+10=-2x-13 22x+18=-2x-13 22x+2x=-18-13 24x=-31/:24 x=-31/24 (w ułamku) g) 4(x-2)-2(x-4) = 5(x+)- 3x 4x-8-2x+8=5x-3x 2x=2x 2x-2x=0 0=0 h)2(x-4)=2(x-1)+6(x+1) 2x-8=2x-2+6x+6 2x-2x-6x=8-2+6 -6x=12/:(-6) x=-2
