Ważne prosze ;) rozwiaz równania a)6xkwadrat+x-1=0 b)5xkwadrat+9x-14=0 c)-xkwadrat-2x-1=0 dziekuje ;)

a)6x²+x-1=0_____a=6____b=1_____c=-1 Δ=b²-4ac=1²-4*6*(-1)=1+24=25 x₁=-b+√Δ/2a=-1+√25/2*6=-1+√25/12 x₂=-b-√Δ/2a=-1-√25/2*6=-1-√25/12 b)5x²+9x-14=0____a=5___b=9____c=-14 Δ=b²-4ac=9²-4*5*(-14)=81+280=361 x₁=-b+√Δ/2a=-9+19/2*5=¹⁰/₁₀=1 x₂=-b-√Δ/2a=-9-19/2*5=²⁸/₁₀=2⁸/₁₀=2⁴/₅ c)-x²-2x-1=0_____a=-1____b=-2_____c=-1 Δ=b²-4ac=(-2)²-4*(-1)*(-1)=4-4=0 ____b_____-2______-2 x₀=-~~~~=-~~~~~~=-~~~~~~=-1 ____2a____2*(-1)___-2 mam nadzieje ze rozczytasz to jest ułamek przed tymi ~~~~~ stoi znak -

a)6x² + x -1 = 0 Δ = b²-4ac Δ = 1² - 4 * 6 * (-1) Δ = 1+ 24 = 25 √Δ = 5 x₁=-b +√Δ/2a =-1 + 5 /12 = -4/12 = - 1/3 x₂=-b - √Δ/2a =-1 - 5 /12 = -6/ 12 = -1/2 b)5x²+9x-14=0 Δ = b² - 4ac Δ = 9² -4*5*(-14)=81+140 = 221 √Δ = 11 x₁= -b + √Δ/2a = -9 + 11 /2*5 = -2/ 10 = -1/5 x₂= -b - √Δ/2a = -9- 11/2*5 = -20/10 = -2 c)-x²-2x-1=0 Δ = b² - 4ac = Δ = (-2)² - 4 * (-1) * (-1) = Δ = 4 + 4 = 8 √Δ = √4*2 √Δ = 2√2 x₁= -b + √Δ/2a = 2 + 2√2 / -2 = 2 * (1 + √2) /-2 = - ( 1 + √2) = 1 - √2 x₂= -b - √Δ/2a = 2 - 2√2 / -2 = 2 * (1 - √2) /-2 = - (1 - √2) = 1 +√2