Rozwiąż równość sin4x=-1 sin(2x+π/3)=√3/2 cos(3x-π/4)=√2/2 cos²x+3cosx+2=0

wszędzie k∈C sin4x=-1 sin4x=sin(3/2π) 4x=3/2π+2kπ x=3/8π+k/2π sin(2x+π/3)=√3/2 sin(2x+π/3)=sin(π/3) 2x+π/3=π/3+2kπ ∨ 2x+π/3=2/3π+2kπ x=kπ ∨ x=π/6+kπ cos(3x-π/4)=√2/2 cos(3x-π/4)=cos(π/4) 3x-π/4=π/4+2kπ ∨ 3x-π/4=-π/4+2kπ x=π/6+2/3kπ ∨ x=2/3kπ cos²x+3cosx+2=0 (cosx+2)(cosx+1)=0 cosx=-2 ∨ cosx=-1 bzdura x=cos(π) x=π+2kπ