Zapisz w postaci sumy algebraicznej : 5(-2x+4y)= -2(4a+2b)= 7(3c-3a+2)= b(a-2b-ab)= -3(6-c)= 3a(4a+3)= (4x-12):4= (-5a+25b):5= (16x-12y):4= (14a-28):7=

5(-2x+4y)= -10x+20y -2(4a+2b)= -8a+(-4b) 7(3c-3a+2)= 21c+(-21a)+14 b(a-2b-ab)=ab-2b²-ab² -3(6-c)= -18+3c 3a(4a+3)=12a²+9a (4x-12):4= x+(-3) (-5a+25b):5= -a+5b (16x-12y):4= 4x+(-3y) (14a-28):7=2a+(-4)

5(-2x+4y)=-10x+20y -2(4a+2b)=-8a-4b 7(3c-3a+2)=21c-21a+14 b(a-2b-ab)=ab-2b do potęgi drugiej-ab do potęgi drugiej -3(6-c)=-18-c 3a(4a+3)=12a do potęgi drugiej+9a (4x-12):4=x-4 (-5a+25b):5=-a+25b (16x-12y):4=4x-3y (14a-28):7= 2a-4