log49 7 = log 0,2 625= log=√3 27= log2 144 - log2 9 = log3 54+log3 1,5= z gory dziekuje .

log49 7 =log₄₉ 7=½log₇ 7=½*1=½ log 0,2 625=log₅₋₁5⁴=-1log₅5⁴=-1*4log₅5=-4 log√3 27=log√₃3³=2*3log3₃=6 log₂144 - log₂9 =log₂(144/9)=log₂16=log₂2⁴=4log₂2=4 log₃54+log₃ 1,5=log₃(54*1,5)=log₃81=log₃3⁴=4log₃3=4

log₄₉ 7 = x (ten + np. tu 49⁺ zapisz jako x tu się tego nie da zapisać:) 49⁺ = 7 (7²)⁺ = 7¹ 7²⁺ = 7¹ 2x = 1 /:2 x = ½ log₄₉ 7 = ½ log₀,₂ 625 = x 0,2⁺ = 625 (2/10)⁺ = 5⁴ (1/5)⁺ = 5⁴ (5⁻¹)⁺ = 5⁴ 5⁻⁺ = 5⁴ -x = 4 /*(-1) x = - 4 log₀,₂ 625 = -4 log√₃ 27 = x (√3)⁺ = 27 (3¹/²)⁺ = 3³ ½x = 3 /*2 x = 6 log√₃27 = 6 Do poniższych stosujemy wzory: loga b + loga c = loga (b*c) loga b - loga c = loga (b/c) log₂ 144 - log₂ 9 = log₂ (144:9) = log₂ 16 = x 2⁺ = 16 2⁺ = 2⁴ x = 4 log₂ 16 = 4 log₃ 4 + log₃ 1,5 = log₃ (54*1,5) = log₃ 81 = x 3⁺ = 81 3⁺ = 3⁴ x = 4 log₃ 81 = 4