opuść nawiasy i doprowadz wyrażenie do jak najprostszej postaci 6+(χ-8)+(3х-9)= 10(χ+2)-(-3-χ)+6= (9-χ)(2+χ)-χ= -6+(χ-8)+4(3χ-9)= 10(χ+2)-(χ+3)+16= (9+χ)(1+χ)-7χ= 6+(χ+18)+(χ-9)= 4(χ-2)-(3-χ)-60= (3-χ)(2+χ)-5χ=3γ=

-11+4x 29+11x 18+5x 50+13x 33+9x 9 15+2x 71+5x 6-5x=3y

6+(χ-8)+(3х-9)= 6+x-8+3x-9= -2+4x-9=-11+4x 10(χ+2)-(-3-χ)+6= 10x+20+3+x=11x+23 (9-χ)(2+χ)-χ= 18+9x-2x-x2-x= 18+7x-x2-x=18+6x-x2=-x2+6x+18 -6+(χ-8)+4(3χ-9)=-6+x-8+12x-36=-14+13x-36=13x-50 10(χ+2)-(χ+3)+16=10x+20-x-3+16=9x+17+16=9x+33 (9+χ)(1+χ)-7χ=9+9x+x+x2-7x=2+10x+x2-7x=x2+3x+2 6+(χ+18)+(χ-9)=6+x+18+x-9=24+2x-9=2x+15 4(χ-2)-(3-χ)-60=4x-8-3+x-60=5x-11-60=5x-71 (3-χ)(2+χ)-5χ=3γ= tu chyba miało być na koncu +3y więc tak licze! (3-χ)(2+χ)-5χ+3y= 6+3x-2x-x2-5x+3y=6+x-x2-5x+3y=-x2-4x+3y+6