Proszę o pomoc z równań: duza 5x+3y=0 klamerka -x-2y=7/.(-5) duza 3u+2u=2/:(-2) klamerka 5u+4u=6 duza 3s+5t=-6 /. (-2) klamerka 1,5s-2t=-3 /. (-2) prosze o pomoć :) dziekuje

1) 5x+3y=0 -x-2y=7 /*(-5) 5x+3y=0 5x+10y = -35 /:5 5x+3y=0 x+10y=-7 5x+3y=0 x=-7-10y 5 *(-7-10y) + 3y= 0 x=-7-10y -35-50y +3y = 0 x=-7-10y -47y = 35 /;(-47) x=-7-10y y = - 35/47 x = -7 - 10*(-35/47) = -7 + 350/47 = -7 + 7 21/47 = 21/47 2) 3u+2u=2/:(-2) 5u+4u=6 -3/2u - u = -1 5u+4u=6 -6/3u=-1 /:(-6/3) 9u=6 /:9 u = -1 * (-3/6) = 3/6 = 1/3 u = 6/9 = 2/3 3) 3s+5t=-6 /. (-2) 1,5s-2t=-3 /. (-2) -6s - 10t = 12 -3s + 4t = 6 /*(-2) -6s-10t=12 6s - 8t = -12 + _______________ -18t = 0 t=0 6s - 8*0 = -12 6s=12 /:6 s=2 t=0 s=2