a)Rozwiąż równanie 2/x=(x-1)² b)4/x+3=x² w a powinno wyjsć x=2 a w b x=-2 i x=1

2/x = (x - 1)² |*x 2 = x(x² - 2x + 1) 0 = x³ - 2x² + x - 2 0 = (x - 2)x² + (x - 2) 0 = (x - 2)(x² + 1) x = 2 4/(x + 3) = x² |*(x + 3) 4 = x²(x + 3) x³ + 3x² - 4 = 0 schemat hornera - | 1 | 3 | 0 | -4 1 | 1 | 4 | 4 | 0 (x - 1)(x² + 4x + 4) = 0 (x - 1)(x + 2)² = 0 x = 1 ∨ x = - 2 w razie pytań na pw