Zapisz i rozwiaz odpowiedni uklad rownan. pole = 126 obwod = 54

ab=126 2a+2b=54 /:2 ab=126 a+b=27→a=27-b b(27-b)=126 -b²+27b-126=0 Δ=b²-4ac=729-504=225 √Δ=15 b₁=(-b-√Δ):2a=(-27-15):-2=21 b₂=(-b+√Δ):2a=(-27+15):-2=6 a₁=27-b=27-21=6 a₂=27-6=21 spr. ab=126 21×6=126 126=126 2a+2b=54 2×6+2×21=54 54=54

( a*b = 126 ( 2a + 2b = 54 /:2 ( a*b = 126 ( a + b = 27 ( a*b = 126 ( a = 27 - b ( (27-b)*b = 126 ( a = 27 - b ( 27b - b² = 126 ( a = 27 - b ( -b² + 27b - 126 = 0 ( a = 27 - b [delta = d] d =729 - 4 *(-) * (-126) d = 729 - 504 d = 225 √d = 15 b₁ = -b - √d /2a b₁ = -27 + 15 /-2 = -42 /-2 = 21 b₂ = -27+ 15 /-2 = -2/-2 = 1 [ b₂ nie spełnia warunków zadania, ponieważ 1* 26 jest spełnia wrunków zadania] ( b = 21 ( a = 27 - b ( b = 21 ( a = 27 -21 ( b = 21 ( a = 6