Znajdź liczbę, której:
a)20% jest równe 2,3-1 3/4
23/10 - 7/4 = 92/40 - 70/40 = 22/40 = 11/20 = 0,55
20% = 0,55
100%= x
x = (0,55)*100% : 20%
x = 2,75
b)150% jest równe 3,2+4 1/3
3,2+4 1/3 = 32/10 + 13/4 = 16/5 + 13/4 = 64/20 + 65/20 = 129/20 = 6,45
150% = 6,45
100% = x
x = (6,45)*100% : 150%
x = 4,3
c)62% jest równe (3 3/4:5 5/8)/(1 2/5:1 1/4)
(3 3/4:5 5/8)/(1 2/5:1 1/4) =
=(15/4 : 45/8) : (7/5 : 5/4)=
= (15/4 *8/45) : (7/5 *4/5)=
= 2/3 : 28/25=
= 2/3*25/28=
= 25/42
62% = 25/42
100% = x
x = 25/42* 100% : 62%
x = 625/651
d)112% jest równe (1 1/3 (2/5+1 3/4))/(2-1 2/45)
(1 1/3 (2/5+1 3/4))/(2-1 2/45) =
[4/3( 2/5 + 7/4)] : ( 2 - 47/45)=
= [ 4/3( 8/20 + 35/20)] : ( 90/45- 47/45)
= [ 4/3*43/20] : ( 43/45)
= 43/15 : (43/45)
= 43/15*(45/43)
= 3
112 % = 3
100% = x
x = 3*100% : 112%
x = 75/28
e)12,3% jest równe (3 1/3-3 1/2)/(5 1/6-6)
(3 1/3-3 1/2)/(5 1/6-6)=
= (10/3 - 7/2) : ( 31/6 - 36/6)=
= (20/6 - 21/6) : (-5/6)=
= (-1/6): ( -5/6)=
= (-1/6)*(-6/5) =
= 1/5
12,3% = 1/5
100% = x
x = 1/5*100% : 12,3%
x = 200/123
