4(2x+3)-2(4y-1)=30 5x+1nad trzy minus y-3 nad cztery a to sie = 3

( 4(2x + 3) - 2(4y - 1) = 30 ( [5x + 1/3] - [y - 3/4] = 3 /*12 ( 8x + 12 - 8y + 2 = 30 ( 4(5x + 1) - 3(y - 3) = 3*12 ( 8x - 8y = 30 - 12 - 2 ( 20x + 4 - 3y + 9 = 36 ( 8x - 8y = 16 /:8 20x - 3y = 36 - 4 - 9 ( x - y = 2 ( 20x - 3y = 23 ( x = 2 - y ( 20(2 - y) - 3y = 23 ( x = 2 - y ( 40 - 20y - 3y = 23 ( x = 2 - y ( -20y - 3y = 23 - 40 ( x = 2 - y ( -23y = -17 /:(-23) ( x = 2 - y ( y = ¹⁷/₂₃ ( x = 2 - ¹⁷/₂₃ ( y = ¹⁷/₂₃ ( x = 1⁶/₂₃ ( y = ¹⁷/₂₃