do 80g 15% roztworu kwasu siarkowego (VI) dodano 20g wody. oblicz Cp powstalego roztworu. nie jestem dobra z chemi :P prosze o obliczenia

cp=ms*100%/mr ms=cp*mr/100%=15%*80g/100%=12g mr1=mr+mw=80g+20g=100g cp1=ms*100%/mr1=12g*100%/100g=12%

Cp1 = 15% mr = 80 g Cp = ms * 100%/mr 15 = 100ms/80g 100 ms = 1200 g ms = 12 g Cp2 = 12 * 100%/80 + 20 Cp2 = 1200/100 = 12 % !!!