Zad 1. Zaogrąglij podane liczby: a) do setek: 14 382;690,1;7971 b)do czesci setnych: 232,367;10,194,89,999; Zad 2. oblicz: 2½-½*∛3⅜+2¹= (¾)⁻¹-(-1⅓)²:0,9= (1⅓)²*(-⅓)⁻²-1,9⁰*3⁻¹=

zad.1 a)14400; 700; 8000 b)232,37; 10,19; 90

1. a)14 382 =14 400 690=700 7 971=8 000 b)232= 230 367=370 10 194=190 89=90 999=1000

a) do setek: 14 382 - 14 400 690 - 700 1 - 100 7971 - 7 800 b)do czesci setnych: 232,367 - 232,400 10,194 - 10,200 89 - 100 999 9- 1000 Zad 2. oblicz: 2½-½*∛3⅜+2¹= 2 * ³√27/8 + 2 = 2 * 3/2 + 2 = 3 + 2 = 5 (¾)⁻¹-(-1⅓)²:0,9= 4/3 - (- 4/3 )² : 0,9 = 4/3 + 16/9 : 9/10 = 12/9 + 16/9 * 10/ 9 = 12/9 + 160/9 = 172/9 = 19 i 1/9 (1⅓)²*(-⅓)⁻²-1,9⁰*3⁻¹= (4/3)² * (-3/1)² - 1 * (-1/3)¹ = 16/9 * 9/1 +1/3 = 16 + 1/3 = 16 i 1/3