tgt2−√3/3 tgt−1− √3/3 tgt=0 jak to obliczyć

tgt2−√3/3 tgt−1− √3/3 tgt=0 tgt² - 2√3/3tgt-1=0 niech tgt=x x²-2√3/3x-1=0 Δ=(2√3/3)²+4= 4*3/9+4= 12/9+36/9= 48/9 √Δ= √48/9= 4√3/3 x₁=[ 2√3/3-4√3/3]/2= -2√3/6=-√3/3 x₂= 6√3/6= √3 zatem tgt= -√3/3 lub tgt=√3