rozwiąż układ równań: zad 1 x+y=1 2x+y=3 zad 2 liczba (-3 ⅓)⁻⁴ jest równa.

x+y=1 /*-2 -2x-2y=-2 2x+y=3 -y=1 y=-1 (-3 ⅓)⁻⁴ = 1/(-10/3)⁴=81/10 000=0,0081

zad.1 x+y=1 2x+y=3 x=1-y 2(1-y)+y=3 x=1-y 2-2y+y=3 x=1-y -y=1 /:-1 x=1-y y=-1 x=1+1 y=-1 x=2 y=-1

1.x+y=1 2x+y=3 x=1-y 2(1-y)+y=3 x=1-y 2-2y+y=3 x=1-y -y=3-2 x=1-y y=-1 x=1-(-1) y=-1 x=2 y=-1 2.(-3⅓)⁻⁴=(-³/₁₀)⁴=-⁸¹/₁₀₀₀₀