zapisz w postaci sumy algebraicznej: (tylko poprosze z obliczeniami) a) (x+1)(x+2)(x+3)= b) (x-2)(x+5)(2x-1) c) (x-4)(x+1)²= d) (2x-3)²(x+2)=

a) (x+1)(x+2)(x+3)=(x²+2x+x+2)(x+3)=(x²+3x+2)(x+3)= x³+3x²+2x+3x²+9x+6=x³+6x²+11x+6 b) (x-2)(x+5)(2x-1)=(x²+5x-2x-10)(2x-1)=(x²+3x-10)(2x-1)= 2x³+6x²-20x-x²-3x+10=2x³+5x²-23x+10 c) (x-4)(x+1)²=(x-4)[x²+2*1*x+1²]=(x-4)(x²+2x+1)=x³+2x²+x-4x²-8x-4= x³-2x²-7x-4 d) (2x-3)²(x+2)=[(2x)²-2*2x*3+3²](x+2)=(4x²-12x+9)(x+2)= 4x³-12x²+9x+8x²-24x+18=4x³-4x²-15x+18 :):)Pozdrowienia:*:*